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Title: Calculus I help? Post by: Kaulus7 on November 20, 2009, 10:57:20 pm Anyone who remembers this?? If so, I'll start listing my problems tomorrow...
Section is Derivatives and the Shapes of Curves. Title: Re: Calculus I help? Post by: Maplen13 on November 21, 2009, 10:46:37 am Ooh, Calculas... I like, but I think I've heard Derivatives before...
Title: Re: Calculus I help? Post by: [5025] on November 21, 2009, 11:10:39 am I can help you with calc 1,2, 3 (multivariate), and differential equations.
Title: Re: Calculus I help? Post by: Kaulus7 on November 21, 2009, 02:30:55 pm Thanks torsion!
I'll edit this in about 10 min. with a problem I have trouble with. Title: Re: Calculus I help? Post by: [5025] on November 21, 2009, 02:56:19 pm No problem. As long as it's not a taylor series, I can help.
Title: Re: Calculus I help? Post by: Kaulus7 on November 21, 2009, 03:34:56 pm Woohoo! We skipped that stuff! (I think we did...)
Title: Re: Calculus I help? Post by: [5025] on November 21, 2009, 03:38:16 pm So, what do you need help with?
Title: Re: Calculus I help? Post by: Kaulus7 on November 21, 2009, 09:59:25 pm I'll have it by tomorrow-it's more complex than I thought. :-\
Title: Re: Calculus I help? Post by: MsRowdyRedhead on November 22, 2009, 01:43:31 am Kaulus, Is this a homework question?
Title: Re: Calculus I help? Post by: [5025] on November 22, 2009, 07:37:17 am Kaulus, Is this a homework question? I was about to mention this. If it is, I wont solve it, I will just give you some tips, or solve a problem similar to it. Title: Re: Calculus I help? Post by: Kaulus7 on November 22, 2009, 11:42:51 am Yeah, don't worry, I can do most of this by myself, it's easier than it looks.
Just to confirm is f"(x)=7x3*(x-1)2+(7x-4)(3x2(x-1)2+2x3(x-1)2) if f(x)=x4(x-1)3? Give me a yes/no answer and I'll check my work. Title: Re: Calculus I help? Post by: [5025] on November 22, 2009, 11:52:24 am No. It's something along the lines of "x^2(x-c)*(c*x^2-8*x+c)
C is a constant, that varies over terms... Title: Re: Calculus I help? Post by: Kaulus7 on November 22, 2009, 10:10:47 pm I could probably do this myself but my mind is addled and I need to go to bed early so...
For what values of c does the polynomial P(x)=x4+cx3+x2 have two inflection points? One inflection point? None? Illustrate by graphing P for several values of c. How does the graph change as c decreases? I know that second derivative is the first step (I hope it is...). But how would I go about to determining the values of c? Guess and check is an option, but I don't think that's what my instructors had in mind... Title: Re: Calculus I help? Post by: [5025] on November 24, 2009, 10:22:20 am Inflection? As in max or min?
Title: Re: Calculus I help? Post by: Kaulus7 on November 25, 2009, 01:08:38 am Inflection as in point of change between the concavity.
Title: Re: Calculus I help? Post by: Michaelz on November 25, 2009, 09:04:34 am Here's a link to some examples of finding inflection points:
http://www.clas.ucsb.edu/staff/lee/Inflection%20Points.htm The basic steps are to take the second derivative and determine the roots (where the equation is 0). Then you have to check that the concavity is changing at that point of the function. In this example the 2nd derivative will have c as a variable. You need to determine for what values of c the function (the 2nd derivative) has 0, 1, 2, etc. roots. |